On 03/07/2011 04:08 PM, Sergio Belkin wrote:
Hi,
I am writing a script that it searchs for a file. I'd want to exit
with status non-zero if the file is not found. But find cannot do
that.
find command only exit with status non-zero one file is not processed
successfully.
locate command con do that, but it cannot find a file from a given directory.
How can I do it?
Thanks in advance!
I find that if I'm in a directory and do a "find <filename>" and it
fails the exit code is 1 (re: $? = 1). So if I'm in a directory
that has files a b c and d and do "find a" I get an exit code of 0 (success) but
if I do a "find e" I get exit code of 1 (failure)
along with a failure message. So in your script you could do:
#!/bin/bash
cd <somedir>
find <filename> 2> /dev/null
if [ "$?" != "0" ]
then
exit 1
fi
Strangely enough, if I'm in a directory and do a "find . -name e" (where e
doesn't exist) I get *no* failed message and an exit code
of 0. I find that a bit odd as I would think that "find e" and "find .
-name e" would be the same thing. Perhaps that's something
to do with the bash shell?
kevin