I guess you can just generate that URL from the bug's ID, then use standard
python urllib or similar to fetch the web page contents. I don't think there's
any bugzilla API call that does what you want though
- Cole
On 01/13/2015 03:35 PM, Ravikumar Patel wrote:
I'll guide you through the steps I've followed to clarify
what I mean. First,
I queried for all bugs for a specific person. I then got a list of bugs for
that person with all of their bug IDs. I clicked on one of the bug ID and it
gave me a page with that bug's summary, status, aliases, product, etc. Once
you get to the bottom of the page, you have a link to it's XML view/page. (see
screenshot below)
Inline image 1
Now I want to get access to this page (using my python script from previous
emails):
Inline image 3
I want to know if I can access this XML page from a corresponding bug ID via a
python script?
Thanks,
Ravi
On Tue, Jan 13, 2015 at 2:25 PM, Cole Robinson <crobinso(a)redhat.com
<mailto:crobinso@redhat.com>> wrote:
I don't know what you mean by 'xml page'
- Cole
On 01/13/2015 02:23 PM, Ravikumar Patel wrote:
> This is a follow up question. How do I now access each bug's XML page now
that
> I have the bug IDs I needed?
>
> On Tue, Jan 13, 2015 at 1:34 PM, Cole Robinson <crobinso(a)redhat.com
<mailto:crobinso@redhat.com>
> <mailto:crobinso@redhat.com <mailto:crobinso@redhat.com>>>
wrote:
>
> On 01/13/2015 12:59 PM, Ravikumar Patel wrote:
> > Hello,
> >
> > I am trying to get the bug ID of all bugs from my Bugzilla account.
Any
> > suggestions as to how I am able to do so? Is it possible that to query
for all
> > projects and then access the bug IDs from each project? If so, then
how?
> >
> > So far my code looks like this:
> >
> > |bz =
bugzilla.Bugzilla(url='https://bugzilla.mycompany.com/xmlrpc.cgi')
> > try:
> > bz.login('name(a)email.com <mailto:name@email.com>
<mailto:name@email.com
<mailto:name@email.com>>
> <mailto:name@email.com <mailto:name@email.com>
<mailto:name@email.com <mailto:name@email.com>>>',
'password');
> > print'Authorization cookie received.'
> > except bugzilla.BugzillaError:
> > print(str(sys.exc_info()[1]))
> > sys.exit(1)|
> >
> > Here is the link to the stackoverflow question page:
> >
http://stackoverflow.com/questions/27869663/how-do-i-query-bugzilla-to-ge...
> >
> > I really need help on this. Any suggestions?
>
> bugs =
bz.query(bz.build_query(assigned_to="your-bugzilla-account"))
> for bug in bugs:
> print bug.id <
http://bug.id> <
http://bug.id>
>
> - Cole
>
>
>
>