I want to extract all information from a bug (comments, creator's name and
email, QA's name and email, etc) and save it to a text file but I'm not
able to. I can only access some of the data. I'm using Bugzilla version
4.2.5. Using *print dir(bz.getbug(8658))*, here is what I have access to
the following (see attachment).
So long story short, I cannot/don't have access to *description*, *dupe_of*
, *assigned_to*/*qa_contact *(can only get email but not the name),
*estimated_time*, *actual_time*, *remaining_time*, getting all *comments *(with
date, text, author, attachments reference) and *attachments *(file, date,
author, description).
But some of these attributes are available as tags on the bug's XML page.
So I thought maybe I could just parse the XML page and get all the info
from there. Do you have any suggestions? Otherwise I'm stuck because I
can't get all the info I need.
Thanks,
Ravi
On Tue, Jan 13, 2015 at 4:04 PM, Cole Robinson <crobinso(a)redhat.com> wrote:
Sorry I didn't consider the auth issue.
Modern bugzilla doesn't use cookies via the xmlrpc API, instead it uses a
token which is API access only. So authenticating via python-bugzilla is
not
going to give you any way of accessing a regular bugzilla URL with auth. So
there's no easy way that I can think of.
What are you trying to achieve exactly? Why do you need the bug XML output?
All that information should be available via the python-bugzilla API, so
maybe
you can achieve what you need in a different way
- Cole
On 01/13/2015 03:56 PM, Ravikumar Patel wrote:
> Thanks for the help. Could you help me with that because I am having
login
> issues from a couple of stuff I found on the web? Or can you provide me
with
> any helpful links?
>
> So far I have looked at these and I keep getting a dummy html page (not
> related to the bug) instead of the XML page for the bug:
>
>
http://stackoverflow.com/questions/189555/how-to-use-python-to-login-to-a...
>
http://stackoverflow.com/questions/11167419/get-xml-data-from-bugzilla-url
>
> On Tue, Jan 13, 2015 at 3:38 PM, Cole Robinson <crobinso(a)redhat.com
> <mailto:crobinso@redhat.com>> wrote:
>
> I guess you can just generate that URL from the bug's ID, then use
standard
> python urllib or similar to fetch the web page contents. I don't
think there's
> any bugzilla API call that does what you want though
>
> - Cole
>
> On 01/13/2015 03:35 PM, Ravikumar Patel wrote:
> > I'll guide you through the steps I've followed to clarify what I
mean. First,
> > I queried for all bugs for a specific person. I then got a list of
bugs for
> > that person with all of their bug IDs. I clicked on one of the bug
ID and it
> > gave me a page with that bug's summary, status, aliases, product,
etc. Once
> > you get to the bottom of the page, you have a link to it's XML
view/page. (see
> > screenshot below)
> >
> > Inline image 1
> >
> > Now I want to get access to this page (using my python script from
previous
> > emails):
> > Inline image 3
> >
> > I want to know if I can access this XML page from a corresponding
bug ID via a
> > python script?
> >
> > Thanks,
> > Ravi
> >
> >
> > On Tue, Jan 13, 2015 at 2:25 PM, Cole Robinson <
crobinso(a)redhat.com <mailto:crobinso@redhat.com>
> > <mailto:crobinso@redhat.com <mailto:crobinso@redhat.com>>>
wrote:
> >
> > I don't know what you mean by 'xml page'
> >
> > - Cole
> >
> > On 01/13/2015 02:23 PM, Ravikumar Patel wrote:
> > > This is a follow up question. How do I now access each bug's
XML page now that
> > > I have the bug IDs I needed?
> > >
> > > On Tue, Jan 13, 2015 at 1:34 PM, Cole Robinson <
crobinso(a)redhat.com <mailto:crobinso@redhat.com>
> <mailto:crobinso@redhat.com <mailto:crobinso@redhat.com>>
> > > <mailto:crobinso@redhat.com <mailto:crobinso@redhat.com>
> <mailto:crobinso@redhat.com <mailto:crobinso@redhat.com>>>>
wrote:
> > >
> > > On 01/13/2015 12:59 PM, Ravikumar Patel wrote:
> > > > Hello,
> > > >
> > > > I am trying to get the bug ID of all bugs from my
Bugzilla account. Any
> > > > suggestions as to how I am able to do so? Is it
possible that to query for all
> > > > projects and then access the bug IDs from each
project? If so, then how?
> > > >
> > > > So far my code looks like this:
> > > >
> > > > |bz = bugzilla.Bugzilla(url='
https://bugzilla.mycompany.com/xmlrpc.cgi')
> > > > try:
> > > > bz.login('name(a)email.com
<mailto:name@email.com>
<mailto:name@email.com
> <mailto:name@email.com>> <mailto:name@email.com <mailto:
name(a)email.com>
> > <mailto:name@email.com <mailto:name@email.com>>>
> > > <mailto:name@email.com <mailto:name@email.com>
<mailto:
name(a)email.com
> <mailto:name@email.com>>
> > <mailto:name@email.com <mailto:name@email.com> <mailto:
name(a)email.com
> <mailto:name@email.com>>>>', 'password');
> > > > print'Authorization cookie received.'
> > > > except bugzilla.BugzillaError:
> > > > print(str(sys.exc_info()[1]))
> > > > sys.exit(1)|
> > > >
> > > > Here is the link to the stackoverflow question page:
> > > >
http://stackoverflow.com/questions/27869663/how-do-i-query-bugzilla-to-ge...
> > > >
> > > > I really need help on this. Any suggestions?
> > >
> > > bugs =
bz.query(bz.build_query(assigned_to="your-bugzilla-account"))
> > > for bug in bugs:
> > > print bug.id <
http://bug.id> <
http://bug.id>
<
http://bug.id>
> > >
> > > - Cole
> > >
> > >
> > >
> > >
> >
> >
>
>