[python-bugzilla] How to get all bug IDs from bugzilla via python script

Ravikumar Patel ravikumarpatel2610 at gmail.com
Tue Jan 13 20:56:22 UTC 2015


Thanks for the help. Could you help me with that because I am having login
issues from a couple of stuff I found on the web? Or can you provide me
with any helpful links?

So far I have looked at these and I keep getting a dummy html page (not
related to the bug) instead of the XML page for the bug:

http://stackoverflow.com/questions/189555/how-to-use-python-to-login-to-a-webpage-and-retrieve-cookies-for-later-usage
http://stackoverflow.com/questions/11167419/get-xml-data-from-bugzilla-url

On Tue, Jan 13, 2015 at 3:38 PM, Cole Robinson <crobinso at redhat.com> wrote:

> I guess you can just generate that URL from the bug's ID, then use standard
> python urllib or similar to fetch the web page contents. I don't think
> there's
> any bugzilla API call that does what you want though
>
> - Cole
>
> On 01/13/2015 03:35 PM, Ravikumar Patel wrote:
> > I'll guide you through the steps I've followed to clarify what I mean.
> First,
> > I queried for all bugs for a specific person. I then got a list of bugs
> for
> > that person with all of their bug IDs. I clicked on one of the bug ID
> and it
> > gave me a page with that bug's summary, status, aliases, product, etc.
> Once
> > you get to the bottom of the page, you have a link to it's XML
> view/page. (see
> > screenshot below)
> >
> > Inline image 1
> >
> > Now I want to get access to this page (using my python script from
> previous
> > emails):
> > Inline image 3
> >
> > I want to know if I can access this XML page from a corresponding bug ID
> via a
> > python script?
> >
> > Thanks,
> > Ravi
> >
> >
> > On Tue, Jan 13, 2015 at 2:25 PM, Cole Robinson <crobinso at redhat.com
> > <mailto:crobinso at redhat.com>> wrote:
> >
> >     I don't know what you mean by 'xml page'
> >
> >     - Cole
> >
> >     On 01/13/2015 02:23 PM, Ravikumar Patel wrote:
> >     > This is a follow up question. How do I now access each bug's XML
> page now that
> >     > I have the bug IDs I needed?
> >     >
> >     > On Tue, Jan 13, 2015 at 1:34 PM, Cole Robinson <
> crobinso at redhat.com <mailto:crobinso at redhat.com>
> >     > <mailto:crobinso at redhat.com <mailto:crobinso at redhat.com>>> wrote:
> >     >
> >     >     On 01/13/2015 12:59 PM, Ravikumar Patel wrote:
> >     >     > Hello,
> >     >     >
> >     >     > I am trying to get the bug ID of all bugs from my Bugzilla
> account. Any
> >     >     > suggestions as to how I am able to do so? Is it possible
> that to query for all
> >     >     > projects and then access the bug IDs from each project? If
> so, then how?
> >     >     >
> >     >     > So far my code looks like this:
> >     >     >
> >     >     > |bz = bugzilla.Bugzilla(url='
> https://bugzilla.mycompany.com/xmlrpc.cgi')
> >     >     > try:
> >     >     >    bz.login('name at email.com <mailto:name at email.com> <mailto:
> name at email.com
> >     <mailto:name at email.com>>
> >     >     <mailto:name at email.com <mailto:name at email.com>
> >     <mailto:name at email.com <mailto:name at email.com>>>', 'password');
> >     >     >    print'Authorization cookie received.'
> >     >     > except bugzilla.BugzillaError:
> >     >     >    print(str(sys.exc_info()[1]))
> >     >     >    sys.exit(1)|
> >     >     >
> >     >     > Here is the link to the stackoverflow question page:
> >     >     >
> http://stackoverflow.com/questions/27869663/how-do-i-query-bugzilla-to-get-all-the-bug-ids-using-python-and-xml-rpc
> >     >     >
> >     >     > I really need help on this. Any suggestions?
> >     >
> >     >     bugs =
> bz.query(bz.build_query(assigned_to="your-bugzilla-account"))
> >     >     for bug in bugs:
> >     >         print bug.id <http://bug.id> <http://bug.id>
> >     >
> >     >     - Cole
> >     >
> >     >
> >     >
> >     >
> >
> >
>
>
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