Hi,
I’ve set version using the Kickstart metadata, It does pick up the if I run something like /bin/echo $version which allows me to see it in the anaconda.log
I’ve tried the following:
$SNIPPET('$cobblersnippetver/common/security/login_configuration')
Which provides no error but the snippet does not run and no output in produced. I believe that $cobblersnippetver is not being converted from the viable.
$SNIPPET($cobblersnippetver/common/security/login_configuration)
This produces an error in the log of a syntax error.
Do you mean It should be call using the first example above?
As the Github cobbler instructions say otherwise
https://github.com/cobbler/cobbler/wiki/Kickstart%20snippets
Cheers
Joe
From: cobbler-bounces@lists.fedorahosted.org [mailto:cobbler-bounces@lists.fedorahosted.org] On Behalf Of James Cammarata
Sent: 18 November 2013 14:46
To: cobbler mailing list
Subject: Re: [cobbler] Cobbler/Snippet Query
There is no limit, but how are you setting $version? Variables in snippet names should work fine (but it should be quoted, ie. $SNIPPET('$version/snippet1))
On Mon, Nov 18, 2013 at 8:38 AM, Madden, Joe <Joe.Madden@mottmac.com> wrote:
Hi all,
I have been playing with snippets for some time now and understand the basics and have had it working.
The Challenge comes where I am trying to ensure that there are versioning between each version of our common snippets that will allow different profiles to use different versions.
I assumed the easiest way to do this would be to only use the subdirectory version of the snippets which would contain a version number, therefore the profile would only ever pick the common snippets from its own version.
For Example:
Common1 Common2
Snippet1 Snippet1
Unfortunately when referencing the $version within the $SNIPPET($version/snippet1) is does not work. Is there a maximum number of subdirectories that snippets can be in?
Cheers
Joe
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